Today is day 3 of the #14G10daysofcode challenge given by Ingressive4good. Today we are given a pretty simple question on leetcode. Palindrome Number (Difficulty - Easy)
Question
Given an integer x, return true if x is palindrome integer.
An integer is a palindrome when it reads the same backward as forward.
For example, 121 is a palindrome while 123 is not.
An example
Input: x = 121
Output: true
Explanation: 121 reads as 121 from left to right and from right to left.
In my opinion , this is a very simple task. I decide to dive into php to solve this problem (been using js for a while tho!).
My approach
-First i converted the numbers to string using php inbuilt function strval( ) . -Next i reversed the string using another inbuilt function strrev( )
That's probably why i decided the language to be php lol!
Next i compared the result gotten from step 1 and 2 with the original integer that was provided,then returned the result of that comparison.
Straightforward and simple! Right?
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